Question

resolva as equações usando Bhaskara (x-3)^2=-2x^2

Answer 1

(x-3)^2=-2x^2
x^2-6x+9=-2x^2
3x^2-6x+9=0

a=3
b=-6
c=9

Δ= (-6)^2 -4 (1) (9)= 36-36 = 0
x=6+-$\sqrt{0}$/2
x1= 6+0/2 =3
x2= 6-0/2 = 3