Question

equaçao de 2 grau 8x2-6x+1=0

Answer 1

a=8
b=-6
c=1

Δ= (-6)²-4×(8)×(1)=36-32=4
bhaskara:(-b+-√Δ)÷(2a)
(-(-6)+-√4)÷(2×(8))
(6+-2)÷(16)
x₁=(6+2)÷16=
8÷16=
1/2
x₂=(6-2)/16=
4/16=
1/4
x₁=1/2
x₂=1/4

Answer 2

8x² - 6x + 1 = 0

a = 8
b = - 6
c = 1

Δ = b² -4 . a . c
Δ = (-6)² -4 . 8 . 1 
Δ = 36 - 32 
Δ = 4

$\mathtt{\dfrac{-b+-~\sqrt{\Delta}}{2~.~a}~~=~~\dfrac{-(-6)+-~\sqrt{4}}{2~.~8}~~=~~\dfrac{6+-~2}{16}} \\ \\ \\ \mathtt{x' = \dfrac{6+2}{16}~~=~~\dfrac{8}{16}~~(\div8)~~=~~ \dfrac{1}{2}} \\ \\ \\ \mathtt{x''= \dfrac{6-2}{16}~~=~~\dfrac{4}{16}~~(\div4)~~=~~\dfrac{1}{4}} \\ \\ \\ \\ \mathtt{Resposta: S\{~\dfrac{1}{2}~~~e~~~\dfrac{1}{4}\}}$