Question

$\alpha \beta ^{2} -\alpha ^{3}$ para $\alpha = -\frac{x}{2}$ e $\beta = 2x$

Answer 1

αβ² - α³ = ¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨α = - x/2 ¨¨¨¨¨¨¨¨¨β = 2x

(-x/2)(2x)² - (-x/2)³ =

( -x/2 * 4x²) - (-x³/8) =

(-4x³)/2 + x³/8 = ¨¨¨¨¨¨¨¨¨¨mmc(2,8) = 8

-16x³/8 + x³/8 = - 15x³/8