Question

preciso urgente dá resposta?????​

Answer 1

Resposta:

a)

[2^(4n+2) * 2^(3n-9)]/2^(3n-2)

=2^(4n+2+3n-9-3n+2) =2^(4n-5)

b)

[3^(2n+1+4n-1)]³ =[3^(6n)]³=3^(18n)

c)

(1/4)^(n+1) * 2^(3n-2)

(2)^(-2n-2)  * 2^(3n-2)

2^(-2n-2+3n-2) =2^(n-4)