Question

Usando integração por partes: integral u d v equals u. v minus integral v d u

Sendo assim, a integral integral x. e to the power of x d xserá igual a:

I. fraction numerator x ² over denominator 2 end fraction e to the power of x plus c

II. e to the power of x plus c

III. x. e to the power of x minus e to the power of x plus c

Answer 1

Oi Lidia :) 
Resposta é alternativa |||  

$\int\limits {xe^x} \, dx \\ \\ x.e^x- \int\limits {e^u} \, du \\ \\ x.e^x-e^x+C$