Question

$log_{x}(6x + 7) = 2$
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Answer 1

log x (6x+7) = 2

x² = (6x +7)

x² -6x -7 = 0

∆=36+28=64 => √∆=8

x'= -b+√∆/2a = 6+8/2 = 14/2 = 7 ✓