• Matéria: Matemática
  • Autor: guipjn
  • Perguntado 9 anos atrás

Calcule pela definição as derivadas parcias de primeira ordem:
a) f(x,y)=x²-xy+2y²
b)f(x,y)= sqrt(3x-y)


Luanferrao: a letra b é raiz de 3x-y?

Respostas

respondido por: Luanferrao
1
Pela definição, temos que:

\boxed{f(x,y) = \frac{\partial\ f}{\partial\ x}}

\boxed{f(x,y)=\frac{\partial\ f}{\partial\ y}}

a)

 f(x,y)=\frac{\partial\ f}{\partial\ x}\\\\ \frac{\partial\ f}{\partial\ x}=2x-y+0\\\\ \boxed{\frac{\partial\ f}{\partial\ x}=2x-y}

f(x,y)=\frac{\partial\ f}{\partial\ y}\\\\ \frac{\partial\ f}{\partial\ y}=0-x+4y\\\\ \boxed{\frac{\partial\ f}{\partial\ y}=4y-x}

b)

f(x,y)=\sqrt{3x-y}\\\\ f(x,y)=\frac{\partial\ f}{\partial\ x}\\\\ \boxed{\frac{\partial\ f}{\partial\ x}=\frac{3}{2\sqrt{3x-y}}}

f(x,y)=\frac{\partial\ f}{\partial\ y}\\\\\  \boxed{\frac{\partial\ f}{\partial\ y}=\frac{-1}{2\sqrt{3x-y}} }


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