Question

Calcule :

$\frac{1}{ \sqrt[4]{ \frac{1}{16} } }$


$\sqrt[3]{1 + \sqrt{49} }$

Answer 1

$a) \frac{1}{ \sqrt[4]{ \frac{1}{16} } } = \frac{1}{ \frac{ \sqrt[4]{1} }{ \sqrt[4]{16} } } = \frac{1}{ \frac{1}{ \sqrt[4]{16} } } = \frac{1}{ \frac{1}{2} } = \frac{2}{1} = 2 \\\\\\ b) \sqrt[3]{1+ \sqrt{49} } = \sqrt[3]{1+7} = \sqrt[3]{8} = \sqrt[3]{2^3} = 2$