Question

Ajude-me por favor na questão do EsFAO ...

Answer 1

$2^{x-1} = \frac{\sqrt{2 \sqrt[3]{2} }}{8 \sqrt[4]{2} }$

$2^{x-1} = \frac{ ( 2. 2^{ \frac{1}{3} } )^{ \frac{1}{2} }}{ 2^{3}. 2^{ \frac{1}{4} } }$

$2^{x-1} = \frac{2^{ \frac{1}{2} }. 2^{ \frac{1}{6} } }{ 2^{3}. 2^{ \frac{1}{4} } }$

$2^{x-1} = \frac{2^{ \frac{4}{6} }}{ 2^{ \frac{13}{4} }}$

$2^{x-1} = 2^-{ \frac{31}{12} }$

$x-1= -\frac{31}{12}$

$x=1- \frac{31}{12}$

$x= \frac{12-31}{12}$

$x= -\frac{19}{12}$