Question

A soma:

log(2/3) + log(3/4) + log(4/5) +...+ log(19/20)

É igual a:
a) -log20
b) -1
c) log2
d) 1
e) 2​

Answer 1

Resposta:

Explicação passo-a-passo:

log(2/3) + log (3/4) + log (4/5) + ... + log (19/20) = $log(\frac{2}{3}.\frac{3}{4}.\frac{4}{5}.....\frac{18}{19}.\frac{19}{20})=log\frac{2}{20}=log\frac{1}{10}=log10^(-1)=-1$

Alternativa b).