Question

desenvolver os quadrados
a) (2x² - 3²)=
b) (3p² + 2q) ² =

Answer 1

a) (2x² - 3²)² = (2x²)² - 2*(2x²)*(3²) + (3²)² = 4x^4 - 36x² + 81

b) (3p² + 2q²)²  = (3p²)² + 2*(3p²)*(2q²) + (2q²) = 9p^4 + 12 p² q² + 4q^4

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02/12/2015
Sepauto - SSRC
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