Question

Dada a função f(x) = y = x² - x, com x E R e y E R, calcule: 

f (1) + 3f (-1) - 5f (3) + f (0)

Answer 1

$f(x) = x^{2}-x \\ f(1) = (1)^{2}-1 \\ \underline{f(1) = 0} \\\\ f(-1) = (-1)^{2}-(-1) \\ f(-1) = 1+1 \\ \underline{f(-1) = 2} \\\\ f(3) = 3^{2}-3 \\ f(3) = 9-3 \\ \underline{f(3) = 6} \\\\ f(0) = 0^{2}-0 \\ \underline{f(0) = 0}$


Substituindo os valores:

$f(1)+3f(-1)-5f(3)+f(0) \\\\ 0+3 \cdot (2)-5 \cdot (6)+0 \\\\ 6-30 = \boxed{\boxed{-24}}$