Question

ALGUEM ME AJUDA PF ( TEOREMA DE PITAGORAS)

Answer 1

Explicação passo a passo:

A)

X^2=10^2 +8^2

X^2=100 +64

X^2=164

X=√164

X=12,8

B)

(12)^2=x^2 +9^2

144=x^2+81

144-81=x^2

63=x^2

X=√63

X=7,93

C)

20^2=x^2 +16^2

400=x^2+256

400-256=x^2

144=x^2

X=√144

X=12

D)

18^2=x^2 +x^2

18^2=2x^2

324=2x^2

324÷2=x^2

162=x^2

√162=x

12,72=x

E)

X^2=(√16)^2 +(√25)^2

X^2=16 +25

X^2=16 +25

X^2=41

X=√41

X=6,40

Se quiser deixa a reposta na raiz mesmo.

Answer 2

FÓRMULA DE PITÁGORAS:

a² + b² = c²

a) 8² + 10² = x²

64 + 100 = x²

164 = x²

$x = \sqrt{164}$

x = 12, 80

b) x² + 9² = 12²

x² + 81 = 144

x² = 144 - 81

x² = 63

$x = \sqrt{63}$

x = 7, 93

c) x² + 16² = 20²

x² + 256 = 400

x² = 400 - 256

x² = 144

$x = \sqrt{144}$

x = 12

d) x² + x² = 18²

2x² = 324

x² = 324 / 2

x² = 162

$x = \sqrt{162}$

x = 12, 72

e) $( \sqrt{16} )^{2} + ( \sqrt{25} ^{2} ) = {x}^{2}$

( 4 )² + ( 5 )² = x²

16 + 25 = x²

41 = x²

$x = \sqrt{41}$

x = 6, 40