Question

√(1/2)^3x-2 = (1/2)^-4x.2^-x+4

Answer 1

$\sqrt{ (\frac{1}{2})^{(3x-2)} } =( \frac{1}{2} )^{-4x}2^{-x+4} \sqrt{ 2^{(2-3x)} } =(2^{-1} )^{-4x}2^{-x+4} 2^{ \frac{2-3x}{2} } =2^{4x}2^{-x+4} 2^{ \frac{2-3x}{2} } =2^{4x-x+4}=2^{3x+4}$


(2-3x)/2=3x+4 então 2-3x=6x+8 logo 9x=-6 por tanto x=-2/3.