Question

Calculei valor numérico  de x-3y/2 - 2x+y/3 para x igual a 1/3 e y igual 2/3

Answer 1

$x- \frac{3y}{2} -2x+ \frac{y}{3} =x-2x- \frac{3y}{2} + \frac{y}{3}=x- \frac{9y}{6} + \frac{2y}{6}=-x- \frac{7y}{6}\\ Agora\; basta\; substituir:\\ \\ -x- \frac{7y}{6}\\ \\=-x- \frac{7}{6}y\\ \\=-\frac{1}{3}-\frac{7}{6}\cdot\frac{2}{3}\\ \\=-\frac{1}{3}-\frac{14}{18}\\ \\=-\frac{6}{18}-\frac{14}{18}=\frac{-6-14}{18}=-\frac{20^{:2}}{18_{:2}}=-\frac{10}{9}$