F(x)=x2+6X+5 É F(x) X elevado ao quadrado +6X+5 alguém pode me ajudar como fazer para montar e resolver esta questão?
Respostas
respondido por:
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Boa tarde!
Solução!
As equação já esta montada,só falta determinar suas raízes usando a formula de Bhaskara.
Equação!
![f(x)= x^{2} +6x+5\\\\\\\
a=1\\\\\
b=6\\\\\
c=5\\\\\\\
Vamos~~substituir~~na~~formula!\\\\\\\
x= \dfrac{-b\pm \sqrt{b^{2}-4.a.c } }{2.a}\\\\\\\\\
x= \dfrac{-6\pm \sqrt{6^{2}-4.1.5} }{2.1}\\\\\\\\\
x=\dfrac{-6\pm \sqrt{36-20} }{2}\\\\\\\\\
x= \dfrac{-6\pm \sqrt{16} }{2}\\\\\\\\\
x= \dfrac{-6\pm 4 }{2}\\\\\\\\\\
Raizes!\\\\\](https://tex.z-dn.net/?f=f%28x%29%3D+x%5E%7B2%7D+%2B6x%2B5%5C%5C%5C%5C%5C%5C%5C%0Aa%3D1%5C%5C%5C%5C%5C%0Ab%3D6%5C%5C%5C%5C%5C%0Ac%3D5%5C%5C%5C%5C%5C%5C%5C%0AVamos%7E%7Esubstituir%7E%7Ena%7E%7Eformula%21%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-b%5Cpm+%5Csqrt%7Bb%5E%7B2%7D-4.a.c+%7D+%7D%7B2.a%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-6%5Cpm+%5Csqrt%7B6%5E%7B2%7D-4.1.5%7D+%7D%7B2.1%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D%5Cdfrac%7B-6%5Cpm+%5Csqrt%7B36-20%7D+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-6%5Cpm+%5Csqrt%7B16%7D+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-6%5Cpm+4+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%0ARaizes%21%5C%5C%5C%5C%5C%0A%0A+%0A%0A%0A%0A%0A%0A "f(x)= x^{2} +6x+5\\\\\\\
a=1\\\\\
b=6\\\\\
c=5\\\\\\\
Vamos~~substituir~~na~~formula!\\\\\\\
x= \dfrac{-b\pm \sqrt{b^{2}-4.a.c } }{2.a}\\\\\\\\\
x= \dfrac{-6\pm \sqrt{6^{2}-4.1.5} }{2.1}\\\\\\\\\
x=\dfrac{-6\pm \sqrt{36-20} }{2}\\\\\\\\\
x= \dfrac{-6\pm \sqrt{16} }{2}\\\\\\\\\
x= \dfrac{-6\pm 4 }{2}\\\\\\\\\\
Raizes!\\\\\")
![x_{1}= \dfrac{-6+4}{2}= \dfrac{-2}{2}=-1\\\\\\\
x_{2}= \dfrac{-6-4}{2}= \dfrac{-10}{2}=-5\\\\\\\\\
\boxed{Resposta:~S=\{-5,-1\}}](https://tex.z-dn.net/?f=x_%7B1%7D%3D+%5Cdfrac%7B-6%2B4%7D%7B2%7D%3D+%5Cdfrac%7B-2%7D%7B2%7D%3D-1%5C%5C%5C%5C%5C%5C%5C%0A+x_%7B2%7D%3D+%5Cdfrac%7B-6-4%7D%7B2%7D%3D+%5Cdfrac%7B-10%7D%7B2%7D%3D-5%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A%7ES%3D%5C%7B-5%2C-1%5C%7D%7D%0A "x_{1}= \dfrac{-6+4}{2}= \dfrac{-2}{2}=-1\\\\\\\
x_{2}= \dfrac{-6-4}{2}= \dfrac{-10}{2}=-5\\\\\\\\\
\boxed{Resposta:~S=\{-5,-1\}}")
Boa tarde!
Bons estudos!
Solução!
As equação já esta montada,só falta determinar suas raízes usando a formula de Bhaskara.
Equação!
Boa tarde!
Bons estudos!
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