Question

$\frac{1}{3} b x^{10} - \frac{1}{3} b x^{9} + \frac{1}{3} b x^{4}$

Answer 1

$\dfrac{1}{3}bx^{10}-\dfrac{1}{3}bx^{9}+\dfrac{1}{3}bx^{4}=\dfrac{1}{3}b(x^{10}-x^{9}+x^{4})=\dfrac{1}{3}bx^4(x^{6}-x^{5}+1)\\\\ =\dfrac{1}{3}bx^4[x^5(x-1)+1]$