Question

lim quando x tende a 2 (x³-8)/(x²-4)

Answer 1

$\lim_{x \to \;2} \frac{x^3-8}{x^2-4} = \lim_{x \to \22} \frac{(x-2)(x^2+2x+4)}{((x -2)(x+2)} = \lim_{x \to \;2} \frac{x^2+2x+4}{x+2} = \frac{2^2+2.2+4}{2+2}= \\ \\ \frac{4+4+4}{4} = \frac{12}{4} =3$