Question

Equacao biquadrada resposta X⁴+2x²-1=0

Answer 1

x$x^{4}+ 2x^{2}-1=0 y^{2}+2y-1=0 delta= 2^{2}-4.1.(-1) delta= 8 \frac{y= -2 +- \sqrt{8}}{2} y'= -1+ \sqrt{2} y''=-1- \sqrt{2} como y= x^{2} x'= 1- \sqrt{2} x''=-1+ \sqrt{2} x'''= -1 - \sqrt{2} x''''= 1+ \sqrt{2}$