Question

Efetue:


6+i/-3i

Ajudemmm

Answer 1

$\frac{6+i}{-3i} = \frac{-3i(6 + i)}{-3i(-3i)} = \frac{-18i-3i^2}{9i^2} = \frac{-18i-3(-1)}{9(-1)}= \frac{3-18i}{-9}= -\frac{1}{3} +2i$